1 = 0

(x + 1)2  =  x2 + 2x + 1

(x + 1)2 – (2x + 1) = x2

(x + 1)2 – (2x + 1) – x(2x + 1) = x2 – x(2x + 1)

(x + 1)2 – (2x + 1)(x + 1) = x2 – x(2x + 1)

(x + 1)2 – (2x + 1)(x + 1) + (2x + 1)2/4 = x2 – x(2x + 1) + (2x + 1)2/4

[(x + 1) - (2x + 1)/2 ]2 = [x – (2x + 1)/2 ]2

(x + 1) - (2x + 1)/2  = x – (2x + 1)/2

x + 1 = x

1 = 0